please help me with this question

please help me with this question
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please help me with this question leeloo.au@gmail.com 06-27-2007
Posted by leeloo.au@gmail.com on June 27, 2007, 5:46 am
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11. Which of the following IP addresses fall into the CIDR block of
110.68.4.0/18? (Choose three.)
A. 110.68.8.32
B. 110.68.7.64
C. 110.67.6.255
D. 110.66.3.254
E. 110.65.5.128
F. 110.64.12.128


The answer given is as following, but I don't think they are right. In
my opinion, there are two right options A&B

B, C, E. A Class A network address with a /18 is 255.255.192.0. The
subnets in the third octet
are 0, 64, 128, 192. The network address in the question is
110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
and E are correct host IDs.


Pure Networks
Posted by leeloo.au@gmail.com on June 27, 2007, 6:16 am
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18. You have a network with a subnet of 172.16.17.0/22. Which are
valid host addresses?
A. 172.16.17.1 255.255.255.252
B. 172.16.0.1 255.255.240.0
C. 172.16.20.1 255.255.254.0
D. 172.16.16.1 255.255.255.240
E. 172.16.18.255 255.255.252.0
F. 172.16.0.1 255.255.255.0

The given answer is E only,but I think A is right too.

A Class B network ID with a /22 mask is 255.255.252.0, with a block
size of 4 in the third
octet. The network address in the question is in subnet 172.16.16.0
with a broadcast
address of 172.16.19.255.


Posted by John Petersen on June 27, 2007, 10:18 am
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On Wed, 27 Jun 2007 03:16:11 -0700

> 18. You have a network with a subnet of 172.16.17.0/22. Which are
> valid host addresses?
> A. 172.16.17.1 255.255.255.252
> B. 172.16.0.1 255.255.240.0
> C. 172.16.20.1 255.255.254.0
> D. 172.16.16.1 255.255.255.240
> E. 172.16.18.255 255.255.252.0
> F. 172.16.0.1 255.255.255.0
>
> The given answer is E only,but I think A is right too.
>
No, only E - check the subnet mask on answer A, it's /30

For the other one, yeh, only A and B look right to me

Posted by Capt. Barbossa on June 27, 2007, 11:31 am
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I am not sure where they got their answers for this. However I'm going
to agree with everybody else and say A and B are the only valid answers.

IP Address: 110.68.4.0
Network Address: 110.68.0.0
Broadcast Address: 110.68.63.255

I checked my subnet math against a subnet calculator and came up with
the same answer you guys did.

leeloo.au@gmail.com wrote:
> 11. Which of the following IP addresses fall into the CIDR block of
> 110.68.4.0/18? (Choose three.)
> A. 110.68.8.32
> B. 110.68.7.64
> C. 110.67.6.255
> D. 110.66.3.254
> E. 110.65.5.128
> F. 110.64.12.128
>
>
> The answer given is as following, but I don't think they are right. In
> my opinion, there are two right options A&B
>
> B, C, E. A Class A network address with a /18 is 255.255.192.0. The
> subnets in the third octet
> are 0, 64, 128, 192. The network address in the question is
> 110.64.0.0, with a broadcast of
> 110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
> and E are correct host IDs.
>

Posted by leeloo.au@gmail.com on June 28, 2007, 2:53 am
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> I am not sure where they got their answers for this. However I'm going
> to agree with everybody else and say A and B are the only valid answers.
>
> IP Address: 110.68.4.0
> Network Address: 110.68.0.0
> Broadcast Address: 110.68.63.255
>
> I checked my subnet math against a subnet calculator and came up with
> the same answer you guys did.
>
> leeloo...@gmail.com wrote:
> > 11. Which of the following IP addresses fall into the CIDR block of
> > 110.68.4.0/18? (Choose three.)
> > A. 110.68.8.32
> > B. 110.68.7.64
> > C. 110.67.6.255
> > D. 110.66.3.254
> > E. 110.65.5.128
> > F. 110.64.12.128
>
> > The answer given is as following, but I don't think they are right. In
> > my opinion, there are two right options A&B
>
> > B, C, E. A Class A network address with a /18 is 255.255.192.0. The
> > subnets in the third octet
> > are 0, 64, 128, 192. The network address in the question is
> > 110.64.0.0, with a broadcast of
> > 110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C,
> > and E are correct host IDs.

thanks,


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