Subnetwork

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Subject Author Date
Subnetwork ardimulder 07-30-2007
---> Re: Subnetwork leeloo.au@gmail ..07-30-2007
Posted by on July 30, 2007, 6:04 pm
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Hello,

I'm from Holland and soon i will do my CCNA examination. I study very
hard for it. Could somebody help me with the next question? I know the
answer is C, but could somebody explain why?

what is the subnetnumber of a host with an ip address of
172.16.210.0/22?

A. 172.16.42.0
B. 172.16.107.0
C. 172.16.208.0
D. 172.16.252.0
E. 172.16.254.0


Pure Networks
Posted by leeloo.au@gmail.com on July 30, 2007, 10:10 pm
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On Jul 31, 9:04 am, ardimul...@gmail.com wrote:
> Hello,
>
> I'm from Holland and soon i will do my CCNA examination. I study very
> hard for it. Could somebody help me with the next question? I know the
> answer is C, but could somebody explain why?
>
> what is the subnetnumber of a host with an ip address of
> 172.16.210.0/22?
>
> A. 172.16.42.0
> B. 172.16.107.0
> C. 172.16.208.0
> D. 172.16.252.0
> E. 172.16.254.0
the third byte of the subnet mark is :
128+64+32+16+8+4=252,so subnet-mark is 255.255.252.0

256-252=4

the hosts of this subnet should be from 172.16.208.1-172.16.213.254

the answer is C


Posted by TechMann2U on July 31, 2007, 3:56 am
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wrote:
> On Jul 31, 9:04 am, ardimul...@gmail.com wrote:> Hello,
>
> > I'm from Holland and soon i will do my CCNA examination. I study very
> > hard for it. Could somebody help me with the next question? I know the
> > answer is C, but could somebody explain why?
>
> > what is the subnetnumber of a host with an ip address of
> > 172.16.210.0/22?
>
> > A. 172.16.42.0
> > B. 172.16.107.0
> > C. 172.16.208.0
> > D. 172.16.252.0
> > E. 172.16.254.0
>
> the third byte of the subnet mark is :
> 128+64+32+16+8+4=252,so subnet-mark is 255.255.252.0
>
> 256-252=4
>
> the hosts of this subnet should be from 172.16.208.1-172.16.213.254
>
> the answer is C

*********************************************************************************************************************

You could also try going to the following site for an explaination
http://www.subnet.persianadmins.com/subnet.htm

~TechMann2U~


Posted by pk on August 7, 2007, 4:30 pm
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ardimulder@gmail.com wrote:

> Hello,
>
> I'm from Holland and soon i will do my CCNA examination. I study very
> hard for it. Could somebody help me with the next question? I know the
> answer is C, but could somebody explain why?
>
> what is the subnetnumber of a host with an ip address of
> 172.16.210.0/22?
>
> A. 172.16.42.0
> B. 172.16.107.0
> C. 172.16.208.0
> D. 172.16.252.0
> E. 172.16.254.0

Write down the address in binary:

172 16 210 0
10101100 00010000 11010010 00000000

then write a /22 mask in binary:

255 255 252 0
11111111 11111111 11111100 00000000

finally, do a logical AND between the two, and you get:

10101100 00010000 11010000 00000000

or, in the usual notation, 172.16.208.0.

If you're going for your CCNA you better learn to do these calculation quite
fast.


Posted by Micheal Watkins on August 23, 2007, 8:31 am
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The range is

172.16.208.0/22 - 172.16.211.255/22

172.16.213.255 belongs to 172.16.212.0


> ardimulder@gmail.com wrote:
>
>> Hello,
>>
>> I'm from Holland and soon i will do my CCNA examination. I study very
>> hard for it. Could somebody help me with the next question? I know the
>> answer is C, but could somebody explain why?
>>
>> what is the subnetnumber of a host with an ip address of
>> 172.16.210.0/22?
>>
>> A. 172.16.42.0
>> B. 172.16.107.0
>> C. 172.16.208.0
>> D. 172.16.252.0
>> E. 172.16.254.0
>
> Write down the address in binary:
>
> 172 16 210 0
> 10101100 00010000 11010010 00000000
>
> then write a /22 mask in binary:
>
> 255 255 252 0
> 11111111 11111111 11111100 00000000
>
> finally, do a logical AND between the two, and you get:
>
> 10101100 00010000 11010000 00000000
>
> or, in the usual notation, 172.16.208.0.
>
> If you're going for your CCNA you better learn to do these calculation
> quite
> fast.
>




other useful resources:
The Federal Communications Commission (FCC)
Telecommunications Industry Association
Electronic and Software Security Products and Services
International Telecommunication Union

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