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Posted by daytime on February 4, 2007, 10:18 am
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> > Hello- I saw this question on a mock exam about why would an
> > administrator change the value of the spanning tree priority of a
> > switch.(it didnt specify how it would change the value)
> > I thought the answer would be to make/deny the switch to be the root
> > bridge.
> > Here is what the wiki says
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> > Each switch has a MAC address and a configurable priority number; both
> > of these numbers make up the Bridge Identification or BID. The BID is
> > used to elect a root bridge based upon the lowest priority number; if
> > this is a tie then the numerically lowest MAC address wins. Because it
> > is next to impossible that two MAC addresses will be the same (they
> > are uniquely assigned), one switch should always be successfully
> > elected as the root bridge with the switch that has the next lowest
> > priority/cost acting as a secondary (backup) root bridge. Other
> > switches in the network that use spanning tree will use the same
> > algorithmic process to calculate the shortest path to the root bridge
> > and so produce a loop free tree topology where multiple paths to the
> > root bridge exist. The priority number is normally left at its default
> > value but can be reconfigured to a lower number if the network
> > administrator wishes a particular switch to be elected; otherwise the
> > whole process is fully automated.
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> > However the answer was -in order to optimize the path that frames take
> > from source to destination
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> > I am wrong to think that you would only change the priority to win/
> > lose the election process
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> the answer is getting to the end result ... you change the priority to
> ensure a particular switch wins the election process ... influencing the
> layer-2 topology and therefore optimizing the path.
Thanks alot for that-I was just thinking that changing the priority
would make the switch the root ,not looking at the bigger picture.
thanks for your feedback-much appreciated.
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